Trapezoid efgh has coordinates e(−3, 4) , f(1, 4), g(3, 1) , and h(−5, 1) . trapezoid e'f'g'h' has coordinates e′(−12, 16) , f′(4, 16), g'(12, 4) , and h′(−20, 4) . trapezoid e'"f"g"h" has coordinates e′′(12, −16), f′′(−4, −16), g′′(−12, −4) , and h′′(20, −4) . which transformations describe why trapezoids efgh and e'"f"g"h" are similar? trapezoid efgh was rotated 90° clockwise and then dilated by a scale factor of 4. trapezoid efgh was dilated by a scale factor of 4 and then rotated 180° counterclockwise. trapezoid efgh was translated 4 units right and 4 units up and then rotated 180° clockwise. trapezoid efgh was dilated by a scale factor of 14 and then reflected across the x-axis.

Trapezoid EFGH has coordinates E(−3, 4) , F(1, 4), G(3, 1) , and H(−5, 1) . Trapezoid E'"F"G"H" has coordinates E′′(12, −16), F′′(−4, −16), G′′(−12, −4) , and H′′(20, −4)

From the coordinates, it can be observed that the coordinates of trapezoid E"'F"'G"'H"' is obtained from the coordinates of trapezoid EFGH by changing the signs of the coordinate points and multiplying them by 4.
Rotation of 180 degrees clockwise/counter clockwise will result in the change of signs of the coordinates points while dilation by a sclae factor of 1/4 will result in the multiplication of each coordinate point by 4.

Therefore, the required transformations are: Trapezoid EFGH was rotated 180 degrees about the origin and dilated by a scale factor of 1/4.

The answer is 225 miles per 4.5 hours. hope this ; )

(-0, -7) is your answer