6-x
/2 = 4
can somone answer this pls?

If it is (6 - x) / 2 = 4

(6 -x) / 2 = 4multiply both sides by 2
6 - x = 8
6 - 8 = x
-2 = x

and if it is 6 - (x/2) = 4multiply both sides by 2
12 - x = 8
12 - 8 = x
4 = x

parenthesis can make a big difference in a problem

(6-x)/2=4
       x2  x2      multiply both sides by 2
 6-x=8
-6    -6           subtract 6 on both sides
    -x=2
   /-x  /-x        divide by -x to get positive x
      x=-2

--or--

6-(x/2)=4
-6         -6              subtract 6 on both sides
   -x/2=-2
    x2    x2              multiply 2 on both sides
    -x   =-4
    /-x    /-x              divide by -x to get positive x
   x  =4

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*