Suppose an investment of $1,800 doubles in value every 7 years. how much is the investment worth after 42 years?

The investment in 42 years will become $115199.88

Step-by-step explanation:

Let the investment model is

A = final amount

P = initial amount

r = rate

t = time

Now, given that

P = $1800

A = 2P = 2×1800 = $3600

t = 7 years

Now, we have to find A for t = 42 years

Hence, the investment in 42 years will become $115199.88

2500

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;