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Mathematics, 26.10.2019 08:43 lilroach4

(10th grade geometry )

to prove that △dfe ~ △gfh by the sas similarity theorem, it can be stated that de/gf=ef/hf and

∠dfe is 4 times greater than ∠gfh.

∠fhg is the measure of ∠fed.

∠dfe is congruent to ∠gfh.

∠fhg is congruent to ∠efd.


(10th grade geometry )to prove that △dfe ~ △gfh by the sas similarity theorem, it

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(10th grade geometry )

to prove that △dfe ~ △gfh by the sas similarity theorem, it can be...

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