3.a prop for the theater club’s play is constructed as a cone topped with a half-sphere. what is the volume of the prop? round your answer to the nearest tenth of a cubic inch. use 3.14 to approximate pi.

The answer is 2,713 in³

The volume (V) of the prop is the sum of the volume of cone (V1) and half of the volume of the sphere (V2): V = V1 + 1/2 * V2

Volume of the cone is:
V1 = π r² h / 3
According to the image,
h = 14 in
r = 9 in
and
π = 3.14
V1 = 3.14 * 9² * 14 / 3 =  1,186.92 in³

The volume of the sphere is:
V2 = π r³ * 4/3
According to the image,
r = 9 in
and
π = 3.14
V2 = 3.14 * 9³ * 4/3 = 3,052.08 in³

The volume of the prop is:
V = V1 + 1/2 * V2
V = 1,186.92 in³ + 1/2 * 3,052.08 in³
V = 1,186.92 in³  + 1,526.04 in³ 
V = 2,712.96 in³ ≈ 2,713 in³