Why is circle 1 similar to circle 2?

circle 1: center (−1, 10) and radius 4.8

circle 2: center (−1, 10) and radius 1.2

circle 1 is congruent to circle 2.
circle 1 and circle 2 have the same center.
circle 2 is a dilation of circle 1 with a scale factor of 3.6.
circle 1 is a dilation of circle 2 with a scale factor of 4.

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

too hard the other guy did it

step-by-step explanation: