An arrow is shot upward. its height h, in feet, is given b the equation h=-16t^2+32+5, where t is the time in seconds. how many seconds does it take until the arrow hits the ground?

The time taken to reach the ground is t=2.146 approx 2 seconds.

Step-by-step explanation:

Given : An arrow is shot upward. Its height h, in feet, is given by the equation , where t is the time in seconds.

To find : How many seconds does it take until the arrow hits the ground?

Solution :

We have given the equation,

where, h is the height in feet and t is the time in seconds.

We have to find in how many seconds does it take until the arrow hits the ground i.e. height became zero or h(t)=0

Substituting in the equation,

Solve by quadratic formula,

Solution of equation is

On comparing, a=-16 , b=32 , c=5

Solution is

We reject t=-0.146.

So, The time taken to reach the ground is t=2.146 approx 2 seconds.

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

898.1666667

step-by-step explanation:

5389/6 = 898.1666667