![\int\limits^4_0 {4x-x^2} \, dx =[2x^2- \frac{1}{3}x^3]^4_0=(32- \frac{64}{3})-(0)= 10.6666666666](/tpl/images/0372/4005/09fec.png)
or aout 10 and 2/312. find the area lying above the x - axis and below the parabolic curve y = 4x - x2.
a....
Mathematics, 13.11.2019 14:31 velazquezemmy45
12. find the area lying above the x - axis and below the parabolic curve y = 4x - x2.
a.8
b.8 1/3
c.10 2/3
d.16
Answers: 1
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