Solve the system using substitution.
2x+2y=38
y=x+3
a.(8,11)
b.(4,7)
c.(35/4, 47/4)
d. (-4-7)

if anyone actually knows how to work this out hmu because i have 10 other problems just like this.

Hi there...

Solve the system using substitution.
2x + 2y = 38
y = x + 3

We need to solve y = x+ 3 for y
substitute x + 3 for y in 2x + 2y = 38
2x + 2y = 38
Now replace x+3 everywhere there's y
2x + 2(x+3) = 38
2x + 2x + 6 = 38
4x + 6 = 38
4x = 38 - 6
4x = 32
x = 32/4
x = 8
Now, we have the number of x which is gonna help us find y
what we gonna do is replace 8 everywhere we see an x so we find y. Please follow me :)

Substitute 8 for x in y = x + 3
y = 8 + 3
y = 11
Final answer : x = 8 and y = 11
The correct option is A

If you have any further questions about my answer please let me know.

By the way I would be happy to help you with the other 10 :) 

Good luck !

The correct answer is c