Let f(x)= (x^2+3x-4) and g(x)= (x+4)
1. find f times g and state the domain
2.find f/g and state the domain

list the steps to do it, so i can lean

I. Multiply the first function by the second one.
f(x)*g(x) = (x^2+3x-4)*(x+4) = x^3 + 3x^2 - 4x + 4x^2 + 12x -16 = x^3 +7x^2 + 8x - 16.
The domain of this new function is the set of all real numbers (R). Other notation: from minus infinity to plus infinity. We came to this conclusion because the new function poses no restrictions; regardless of which x-value you take, you will get the appropriate y-value.

II. f(x)/g(x) = (x^2+3x-4)/(x+4) =
Ask yourself: which two numbers add up to 3 and multiply to -4? It's -1 and 4. Now we can represent f(x) as (x-1)(x+4).
Since we're dividing these 2 brackets by g(x)=x+4, we may now cancel (x+4). All that's left is x-1.
The domain here is the same as in the previous task - it is R.