The vertices of ∆abc are a(2, 8), b(16, 2), and c(6, 2). the perimeter of ∆abc is , and its area is square units.

The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). The perimeter of ∆ABC is  30  units, and its area is  2  square units.

Perimeter is 32.4 unts

Area is 30.1 square units.  

Step-by-step explanation:

Given the vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). we have to find the area and perimeter of triangle ABC.

By distance formula,

Perimeter=AB+BC+AC=15.2+7.2+10=32.4 units

Now, we find the area of triangle

By Heron's formula

Area is 30.1 square units.      

the answer is 62

the answer is:

mean: 6

mad: 2.14