What does it mean to be “in the black? ”
a.
your financial records are in good order.
b.
your financial records are being called into question.
c.
you have more credits than debits.
d.
you have more debits than credits.

belinda keeps a record of her expenses for the week as shown:

bus fare $8.70
lunch out $7.35
hair cut $16
movie rental $5.95

what is the total of belinda’s expenses for the week?
a.
$22.16
b.
$23.60
c.
$37.90
d.
$38.00

niah earns $7.25 per hour at her part-time job that she works at 18 hours per week. to earn some extra money, niah her friend out with her dog walking service. it is possible to walk more than one dog at a time, and niah’s friend pays her $9 per dog for each half hour walked. niah walks dogs on 3 different days this week, as listed below. what is the total amount of earnings niah had this week?

monday: 3 dogs for 0.5 hours
wednesday: 2 dogs for 0.5 hours and 1 dog for 0.5 hours
thursday: 2 dogs for 1 hour
a.
$175.50
b.
$195.75
c.
$202.50
d.
$220.50

1.true 2.false? ? i think. .

step-by-step explanation:

answer: h

step-by-step explanation:

246

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.