If the vertices of triangle bcd are b(-3,3) and c(3,5) and d(-1,0). what is the perimeter?
a) 10.98
b) 11.41
c) 16.33
d) 17.00

D ( BD ) = √( 2² + 3² ) = √(4+9) = √13 ≈ 3.61
d ( DC ) = √( 4² + 5² ) = √(16+25) = √41 ≈6.40
d ( CB ) = √( 6² + 2² ) = √(36+4) = √40 ≈ 6.32
The perimeter:  3.61 + 6.40 + 6.32 = 16.33

C ) 16.33   

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