How to divide 4y^3-14y^2/2y^2

[ 4y^3 - 14y^2 ] / [ 2y^2 ]

= [ 4y^(2+1) - 14y^2 ] / [ 2y^2 ]

= [ 4y^2 * y - 14y^2 ] / [ 2y^2 ]

= [ 2y^2 * 2y - 2y^2 * 7 ] / [ 2y^2 ]

= [ 2y^2 * (2y - 7) ] / [ 2y^2 ]

= 2y - 7 < this is the answer

I hope this helps. =)