Find the distance and midpoint for (2, 0, -2) and (5, -4, 6)

Hi, It is well simples:

The distance between two points is :

d( A, B) = √[ (xb - xa)^2+(yb - ya)^2+(zb - za)^2]

Then,

A = (xa, ya, za )

B = (xb , yb , zb)

We know:

A = ( 2 ,0 ,-2)

And,

B = (5 , -4 , 6)


xb - xa = 5-2 <=> 3

yb - ya = -4 - 0 <=> -4

zb - za = 6 - (-2) <=> 8

Then us stay:

d( A, B) = √[ (3)^2 + (-4)^2+(8)^2]

= √( 9 + 16 + 64)

= √( 25 + 64)

= √(89)

Its equal to d=7.07in