There is a beaker of 3.5% acid solution and a beaker of 6% acid solution in the science lab. mr. larson needs 200ml of 4.5% acid solution for an experiment. how many of each solution should he combine?

Below are the choices:

A. 80 mL of the 3.5% solution and 120 mL of the 6% solution 

B. 120 mL of the 3.5% solution and 80 mL of the 6% solution 

C. 140 mL of the 3.5% solution and 60 mL of the 6% solution 

D. 120 mL of the 3.5% solution and 80 mL of the 6% solution

Let fraction of 3.5% in final solution be p. 

p * 3.5 + (1 - p) * 6 = 4.5 

3.5p + 6 - 6p = 4.5 

2.5p = 1.5 

p = 3/5 

3/5 * 200 = 120 

Therefore the answer is B. 120 ml of 3.5% and 80 ml of 6%.

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12