Aquadratic equation of the form 0 = ax2 + bx + c has a discriminant value of –16. how many real number solutions does the equation have? me

When the discrimiatnt is less than 0, the equation has 2 complex roots (0 real roots)

-16<0

it is less than 0

there are 0 real solutions

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)

The equation is y=17(7)+600 and it equals 717