Given δabe is an isosceles triangle with ∠abe = 100° and δmnp is an isosceles triangle with one base angle measuring 40°. are the two triangles, δabe and δmnp similar? if so, by what criterion?

The triangles ABE and MNP are similar because the three corresponding angles are equal (AAA Criteria)

Step-by-step explanation:

we know that  

An isosceles triangle has two equal sides and two equal angles. The two equal angles are called the base angles and the third angle is called the vertex angle

The triangle ABE is an isosceles triangle with the vertex angle m∠ABE equal to

so

m∠BAE=m∠AEB-------> base angles

m∠BAE+m∠AEB+m∠ABE= ------> sum of internal angles of triangle

Find m∠BAE

2m∠BAE=

m∠BAE=

The measure of the angles of triangle ABE are

The triangle MNP is an isosceles triangle with the base angle m∠NMP and  m∠NPM equal to

so

m∠MNP+m∠NMP+m∠NPM= ------> sum of internal angles of triangle

Find m∠MNP (vertex angle)

m∠MNP=

m∠MNP=

The measure of the angles of triangle MNP are

therefore

The triangles ABE and MNP are similar because the three corresponding angles are equal (AAA Criteria)

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

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