The radius of a molybdenum atom is 136 pm. how many molybdenum atoms would have to be laid side by side to span a distance of 1.10 mm?

If the radius of a molybdenum atom is 136pm, the diameter would be 272pm. 1pm is 1e^-9 of a mm. Therefore, 1mm is 1,000,000,000pm so 1.3mm is 1,300,000,000pm and 1,300,000,000pm/272pm is 4,779,412. So it would take that many molybdenum atoms laying side by side to span a distanc eof 1.3mm

Do the math. she originally had 50 dollars on her gift card and she had 12 dollars left on her gift card after she finished her shopping spree. if you subtract 50 minus 12 you get thirty eight dollars as your answer. so therefore, ciara spent 38 dollars total o