What is the standard form equation of the line shown below?

graph of a line going through negative 1, 5 and 2, 4

x + 3y = 14

5x + 3y = 14

y = negative one thirdx + fourteen thirds

y − 4 = negative one third(x − 2)

(-1,5)(2,4)
slope = (4 - 5) / (2 - (-1) = -1/3

y = mx + b
slope(m) = -1/3
use either of ur points (2,4)...x = 2 and y = 4
now sub and find b, the y int
4 = -1/3(2) + b
4 = -2/3 + b
4 + 2/3 = b
12/3 + 2/3 = b
14/3 = b

so ur equation is : y = -1/3x + 14/3however, this is not ur answer because it is not in standard form.

y = -1/3x + 14/3
1/3x + y = 14/3multiply both sides by 3
x + 3y = 14 <=== standard form