What is the midpoint of the x-intercepts of f(x)=(x-2)(x-4

The midpoint of the x-intercepts of f(x) is (3,0).

Step-by-step explanation:

The given function is

To find the x-intercepts equation f(x) equals to 0.

Using zero product property, equate each factor equals to 0.

The x-intercepts are (2,0) and (4,0). The midpoint of x-intercepts of f(x) is

Therefore midpoint of the x-intercepts of f(x) is (3,0).

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )