the solutions to 15(2a – 2) = 5(a2 – 1) are:
a = 1, a = –1
a = 5, a = –1
Mathematics, 25.08.2019 10:30 alliemeade1
Math
the solutions to 15(2a – 2) = 5(a2 – 1) are:
a = 1, a = –1
a = 5, a = –1
a = 5, a = 1
Answers: 2
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Math
the solutions to 15(2a – 2) = 5(a2 – 1) are:
a = 1, a = –1
a = 5, a = –1
the solutions to 15(2a – 2) = 5(a2 – 1) are:
a = 1, a = –1
a = 5, a = –1
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