![sec(x)=-\sqrt{2}\qquad \begin{cases} sec(\theta)=\cfrac{1}{cos(\theta)} \end{cases} \\ \quad \\ \cfrac{1}{cos(x)}=-\sqrt{2}\implies \cfrac{1}{-\sqrt{2}}=cos(x) \\ \quad \\ cos^{-1}\left( \cfrac{1}{-\sqrt{2}} \right)=cos^{-1}[cos(x)] \\ \quad \\ cos^{-1}\left(- \cfrac{1}{\sqrt{2}} \right)=x \\ \quad \\ \textit{now, check your Unit Circle for those }\measuredangle x](/tpl/images/0486/3030/49436.png)
Use a graph to solve the equation on the interval
[−2π, 2π].
(enter your answers as a c...
Mathematics, 30.01.2020 15:43 kaylahill14211
Use a graph to solve the equation on the interval
[−2π, 2π].
(enter your answers as a comma-separated
sec x = −√2
Answers: 3
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