If the digits of a three-digit number are reversed in order, then the sum of the new resulting number and the original number comes out to be 665. the difference of the two numbers is 297. the tens’ digit place is two times the hundreds’ place digit.

If is the digit in the s place (e.g. is in the ones place, is in the tens place, etc), then the original number is



Reversing the digits gives the number



Adding these together results in



Subtracting (presumably the new number from the original number) yields



If the tens place contains twice the digit in the hundreds place, then



So you have the following system:



Solving the system should yield , so the original number is 481.

Iwould like to think so. what’s the question you need with?

Where is the table?