Mathematics, 18.08.2019 10:30 samvgesite
8c^2-88c+242 how do you solve this?
Answers: 1
![8c^2-88c+242=2(4c^2-44c+121)=2\left[(2c)^2-2\cdot2c\cdot11+11^2\right]\\\\=2(2c-11)^2](/tpl/images/0175/8228/42f7b.png)
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