a bag contains 3 black, 4 red, 3 yellow, and 2 green marbles. what is the probability of drawing a black and then a red marble out of the bag without replacing the black marble before drawing the red marble?

Ok so there is a total of 12 marbles. 

drawing a black is a probability of 3/12. drawing a red is a probability of 4:12

So first it is 3/12 and then because three are drawn instead of out of 12 it is out of 9 for red, so 4/9

3/12 x 4/9 

the answer is 1/9

1935/10,000= 387/2000the answer to the question is c