Find the difference
5 2/3 - 3 1/5
a. 5 2/3
b. 8 13/15
c. 2 7/15
d. 3 1/5

To find the extreme values of a function f(x. y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x, y)=xy

State if the two triangles are congruent. if they are, state how you know?

The distributive property allows you to say that 3(x − 1) = 3x −