What is the probability that the second digit of a lock combination is odd if the first digit is odd and the digits are not allowed to repeat?

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

is there supposed to be a diagram or a graph for this one? ?

step-by-step explanation: