The answer is the option A ![1](/tpl/images/0368/8696/8aa3f.png)
Step-by-step explanation:
we have
![m\frac{7}{12}](/tpl/images/0368/8696/4d93a.png)
The solution of this inequality is the interval------> ![(\frac{7}{12}, infinite)](/tpl/images/0368/8696/96c94.png)
All real numbers greater than ![\frac{7}{12}](/tpl/images/0368/8696/7f36c.png)
Remember that
------> using a calculator
so
![m0.58](/tpl/images/0368/8696/2ba3c.png)
we know that
If a number is a solution of the inequality
then
the number must satisfy the inequality
Verify each case
case A) ![m=1](/tpl/images/0368/8696/52210.png)
substitute the value of m in the inequality and compare
------> is true
therefore
the number
is a solution
case B) ![m=-1](/tpl/images/0368/8696/bc066.png)
substitute the value of m in the inequality and compare
------> is not true
therefore
the number
is not a solution
case C) ![m=-9](/tpl/images/0368/8696/6a4c9.png)
substitute the value of m in the inequality and compare
------> is not true
therefore
the number
is not a solution
case D) ![m=-5](/tpl/images/0368/8696/e7eca.png)
substitute the value of m in the inequality and compare
------> is not true
therefore
the number
is not a solution