The times that gym members spend on a treadmill are normally distributed with a mean of 20 min and a standard deviation of 8 min. there 240 who will use a treadmill today. about how many gym members are expected to spend 4 min and 36 min on a treadmill today?

Given:
xbar = 20 min
standard deviation = 8 min
total sample = 240

Required:
how many gym members are expected to spend 4 min and 36 min on a treadmill today

Solution:
sd² = (∑(x - xbar)²) / N - 1

there are 42 gym members at 4 minutes and 200 gym members in 36 minutes.

put like terms together.orremember that the 45 becomes negative when moved to the other side.orthe minuses cancel out.