20 points

show that the statement is true.
if j k has endpoints j( 7, 0) and k (-5, -4 ), then the midpoint m of j k lies in quadrant iv.

Midpoint = ( 7 + (- 5 )/2) , ( 0 + (-4)/2)
(7-5/2) , (0-4/2)
(2/2) , (-4/2)
(1 , -2)<-- this point will be in quadrant 4 see it in graph

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

0 = ( 2 - 4 ) ( p + q )0 = ( 2 - 4 ) ( 2 + 5 i ),   by multiplying these0 = ( 4 + 10 i - 8 - 20 i )0 = 4 - 8 + 10 i - 20 i0 = - 4 -10 i   0 = 2 ( - 2 - 5 i )0 / 2 = - 2 - 5 i- 2 - 5 i = 0- 5 i = 2i = 2 / - 5

Set up a system of equations