What is the density of a bowling ball with a mass of 3.0 kg and a volume of 0.0050 m3?

In order to find the density of the bowling ball, ρ , you must determine the mass one unit of volume of this bowling ball would have.

Notice that the problem provides you with the volume of the bowling ball expressed cubic meters, m3 , which means that one unit of volume would be 1 m3 .

Now, you know that a volume of 0.0050 m3 has a mass of 3.0 kg . You can use this known proportion as a conversion factor to figure the mass of 1 m3

1m3⋅3.0 kg0.0050m3=600 kg

So, you know that one unit of volume has a mass of 600 kg , which means that the bowling ball's density is equal to

ρ=6.0⋅102kg m−3−−−−−−−−−−−−−−−−−

The answer is rounded to two sig figs.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: