What is the density of a bowling ball with a mass of 3.0 kg and a volume of 0.0050 m3?

In order to find the density of the bowling ball, ρ , you must determine the mass one unit of volume of this bowling ball would have.

Notice that the problem provides you with the volume of the bowling ball expressed cubic meters, m3 , which means that one unit of volume would be 1 m3 .

Now, you know that a volume of 0.0050 m3 has a mass of 3.0 kg . You can use this known proportion as a conversion factor to figure the mass of 1 m3

1m3⋅3.0 kg0.0050m3=600 kg

So, you know that one unit of volume has a mass of 600 kg , which means that the bowling ball's density is equal to

ρ=6.0⋅102kg m−3−−−−−−−−−−−−−−−−−

The answer is rounded to two sig figs.

17

step-by-step explanation:

answer: the answer is 30 miles per hour.

ft/s -> mphmph = ft/s 1.466667mph = 44 divided by 1.466667mph = 30.00000

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