What are the center and radius of the circle defined by the equation ?
x^2-y^2-6x+10y+25=0

The given equation represents a circle with center at (3,−5) and radius 3.

x2+y2−6x+10y+25=0 can be written as

x2−6x+y2+10y+25=0 or

x2−6x+9+y2+10y+25=9 or

(x−3)2+(y+5)2=32 or

(x−3)2+(y−(−5))2=32

This is the locus of a point which moves so that it moves at constant distance of 3 from the point (3,−5).

Hence the given equation represents a circle with center at (3,−5) and radius 3.

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!