Mathematics, 17.09.2019 13:30 cbyearty56361
At 9am the outside temperature was -3 degree by the noon the temperature was 12 degree a news reporter said it was getting warmer outside. why is this incorrect?
Answers: 1
Mathematics, 21.06.2019 20:00, cutecupcake678
Apatient is to be given 35 milligrams of demerol every 4 hours. you have demerol 50 milligrams/milliliter in stock. how many milliliters should be given per dose?
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Mathematics, 21.06.2019 20:30, Destiny8372
Joe has some money in his bank account he deposits 45$ write an expression that represents the amount of money in joe's account
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Mathematics, 21.06.2019 21:30, chrisgramjooooo2366
In δabc shown below, ∠bac is congruent to ∠bca: triangle abc, where angles a and c are congruent given: base ∠bac and ∠acb are congruent. prove: δabc is an isosceles triangle. when completed (fill in the blanks), the following paragraph proves that line segment ab is congruent to line segment bc making δabc an isosceles triangle. (4 points) construct a perpendicular bisector from point b to line segment ac . label the point of intersection between this perpendicular bisector and line segment ac as point d: m∠bda and m∠bdc is 90° by the definition of a perpendicular bisector. ∠bda is congruent to ∠bdc by the definition of congruent angles. line segment ad is congruent to line segment dc by by the definition of a perpendicular bisector. δbad is congruent to δbcd by the line segment ab is congruent to line segment bc because consequently, δabc is isosceles by definition of an isosceles triangle. 1. corresponding parts of congruent triangles are congruent (cpctc) 2. the definition of a perpendicular bisector 1. the definition of a perpendicular bisector 2. the definition of congruent angles 1. the definition of congruent angles 2. the definition of a perpendicular bisector 1. angle-side-angle (asa) postulate 2. corresponding parts of congruent triangles are congruent (cpctc)
Answers: 1
At 9am the outside temperature was -3 degree by the noon the temperature was 12 degree a news report...
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