In the diagram, polygon abcd is flipped over a line of reflection to form a polygon with its vertices at a′, b′, c′, and d′. points a′, b′, and d′ are shown, but the line of reflection and point c′ are not.

the line of reflection is (x=4,y=4, x=5, y=5) and the coordinates of c′ are(5,2/6,2/7,2/12,2) .

Line of reflection : x=5

Coordinates of C′ : (6,2)

Step-by-step explanation:

Consider the below figure attached with this question.

From the below figure it is clear that the vertices of polygon ABCD are A(1,6), B(3,5), C(4,2) and D(1,2).

The vertices of image are A'(9,6), B'(7,5) and D'(9,2).

The preimage and image of point A are A(1,6) and A'(9,6) respectively. Here, the y-coordinate is same it means the figure ABCD reflected across a vertical line which is passes through the midpoint of A(1,6) and A'(9,6).

Therefore, the line of reflection is x=5.

Since the figure is reflected across x=5, so the rule of reflection is

The coordinates of point C are (4,2).

Therefore, the coordinates of C′ are (6,2).

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet