The soccer team is selling keys chains to raise money for the team. they ordered 100 key chains that cost $0.25 each. there is a flat shipping rate of $8. the team sells the key chains for $2 each. write an algebraic inequality to find the fewest number of key chains, k, the team must sell to make the profit. what is the fewest number of key chains the team must sell to make a profit? show your work and explain your thinking.

Step-by-step explanation:

According to the given information, the team invested

, that is, $25 on key chains.

With the shipping, .

So, the invested 33$. That means they need to sell in order to have an income greater than $33 to make profits, that's the condition.

Therefore, this situation can be modeled as

In words, the sell $2 per key chain must obtaine more than $33.

Then, we solve for

So, the need to sell 17 key chains to make profits. Notice, if they sell 16 they would make $32, which is under the condition to make profits.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~