Marie has a small copy of rene magritte's famous painting, the schoolmaster. her copy has dimensions 2 inches by 1.5 inches. the scale of the copy is 1 in.: 40 cm

a. find the dimensions of the original painting.

b. find the area of the original painting.

c. since 1 inch is 2.54 cm, find the dimensions of the original painting in inches.

d, find the area of the original painting in square inches.

Since the scale is 1 in : 40 cm

2 in ( 40 cm / 1 in) = 80 cm

1.5 in ( 40 cm / 1 in) = 60 cm

80 cm by 60 cm

A =  80 cm x 60 cm = 4800 sq cm

80 cm ( 1 in / 2.54 cm) = 31.5 in

60 cm ( 1 in / 2.54 cm) = 23.6 in

A = 31.5 in x 23.6 in = 743.4 sq in

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²