Cara collected data from 10 students about what their favorite number was between 1 and 10.
the students responses were: 1, 2, 2, 4, 5, 6, 6, 8, 8, 8
what is the absolute deviation?
a) 2.2
b) 5
c) 22
d) 50

Option A - 2.2

Step-by-step explanation:

Given : Data of 10 students

The students responses were: 1, 2, 2, 4, 5, 6, 6, 8, 8, 8

To find : The absolute deviation

Solution :

Step 1: We calculate the mean.

Step 2: Then we calculate how far away each data point is from the mean using positive distances these are known as absolute deviations.

Data pointDistance from mean

 1                        |5-1| =4

 2                       |5-2| =3

 2                       |5-2| =3

 4                       |5-4| =1

 5                       |5-5| =0

 6                       |5-6| =1

 6                       |5-6| =1

 8                       |5-8| =3

 8                       |5-8| =3

 8                       |5-8| =3

Step 3: Add the deviations together.

Step 4: Finally Divide the sum by the number of data points to get mean of absolute deviation.

Therefore,Option A is correct the mean absolute deviation is 2.2.

one peck is 9.309 quarts

9.309x 2

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7