Abaseball is hit straight up at an initial velocity of 150 m/s. what will be the baseball's speed when it hits the ground?

Step-by-step explanation:

It is given that,

A baseball is hit straight up at an initial velocity of 150 m/s. Firstly calculating the maximum height of the balloon. It can be calculated suing third equation of motion as :

At maximum height v = 0

h = 1147.95 m

or

h = 1148 m

We have to find the baseball's speed when it hits the ground. At this point, its initial velocity is 0 and when its hits the ground its velocity is v'. Again using third equation of motion and finding the value of v' as :

v'= 150 m/s

When the baseball hits the ground, its speed is equal to 150 m/s. Hence, this is the required solution.

step-by-step explanation:

i am not sure sorry : c

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option