Given the box plot, will the mean or the median provide a better description of the center? box plot with min at 11, q1 at 22.5, median at 34.5, q3 at 32, max at 37.5 the mean, because the data distribution is symmetrical the mean, because the data distribution is skewed to the left the median, because the data distribution is skewed to the left the median, because the data distribution is skewed to the right

The median, because the data distribution is skewed to the left

EXPLANATION

Given the box plot with the following parameters: 
Minimum value at 11
First Quartile, Q1 at 22.5
Median at 34.5
Third Quartile, Q3 at 36
Maximum value at 37.5

First, we notice that the data distribution is skewed to the left because the median (34.5) is closer to the third quartile (36) than to the first quartile
(22.5).

Furthermore, we know that the mean provides a better description of the center when the data distribution is symmetrical while the median provides a better description of the center when the data distribution is skewed.

Therefore, we conclude that for the given box plot, the median will provide a better description of the center because the data distribution is skewed to the left.

From the box plot given, the data is skewed to the left as the distribution has a longer tail to the left of the distribution. Hence, the median is the best measure of center.

When a distribution has a longer tail to one of its sides, then it is said to be skewed. Hence, since the tail is longer to the left, it is said to be left skewed.

For skewed distributions, the median is the best measure of center.

Therefore, The median is the best measure of center because the data distribution is skewed to the left.

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I’d say letter a..

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