Anumerical pass code is required to open a car door. the pass code is five digits long and uses the digits 0–9. numbers may be repeated in the pass code. how many different pass codes exist

100,000

Step-by-step explanation:

A numerical pass code is required to open a car door.

The pass code is five digits long and uses the digits 0–9.

So, total number of possible digits will be 10

Condition:-

Total number of possible pass code = __×__×__×__×__

For each blank space we have 10 choices to fill because digit repeated. So, every blank space 10 possible digits.

Total number of possible pass code = 10×10×10×10×10

                                                            = 10⁵

                                                            = 100,000

Hence, Total number of pass code form will be 100,000

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870

im with everythinglos so yeahhhhh

step-by-step explanation: