What is the solution of the equation 14^x=5?
round your answer to the nearest ten-thousandth.

x = 0.6099

Step-by-step explanation:

To solve the question, take the logarithm of both sides to base 10. then apply the law of logarithms that states that

log aˣ = x log a

As such, 14^x=5

log 14^x= log 5

x log 14 = log 5

x = log 5 / log 14

x = 0.60985

To the nearest nearest ten-thousandth, it becomes

x = 0.6099

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb