The probability that emma has heart disease is 0.6. she decides to take a test for the disease that is 80% accurate. what is the probability that emma has heart disease and the test predicts heart disease?

The probability that Emma has heart disease and the test predicts heart disease is:

                                48%

Let A denote the event that Emma has a heart disease.

and B denote the event that the test predicts accurate.

Hence, A∩B denote the event that Emma has heart disease and the test predicts heart disease.

From the given equation we have:

             P(A)=0.6

and P(B)=80%=0.8

As we know that event A and event B are independent.

Hence, we have:

P(A∩B)=P(A)×P(B)

⇒  P(A∩B)=0.6×0.8

⇒  P(A∩B)=0.48=48%

                Hence, the probability is:

                           48%

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

oof cheaters cheat because they’re lazy that’s why i cheat xd

: )

step-by-step explanation: