Factorise and solve the quadratic equations below.

x^2+11x+24=0

X² + 11x + 24 = 0

24*1 = 24

We think of 2 numbers that multiply to give 24 and add up to give 11

The 2 numbers are 8 and 3.

8*3 = 24      and  8 + 3 = 11

So the 11x in    x² + 11x + 24 = 0

Replace 11x with (3x + 8x)

 x² + 11x + 24 = 0

x² + 3x + 8x + 24 = 0            Factorize.

x(x + 3) + 8(x + 3) = 0

(x + 3)(x + 8) = 0

That means:

x + 3 = 0    or  x + 8 = 0

x = 0 - 3                x = 0 - 8

x = -3        or        x = -8

Therefore:  x² + 11x + 24 = 0  is (x + 3)(x + 8) = 0   and x = -3 or x = -8

Hope this helps.

C. i believe it is (5×(-20))+(100×(0.7))

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

f(-2) = -3f(1) = 6 . . . estimated from f(x) = (x+2)^2-3, which matches points on the graph (-1,-2) and (0, 1)

so the change in y-value for function f is (6 )) = 9.

the table tells us

g(-2) = 1g(1) = 31

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).