What is the largest of three consecutive positive integers if the sum of the smaller two integers is 11

Let, the numbers are: x, (x+1), (x+2)
Now, x+x+1 = 11
2x + 1 = 11
2x = 10
x = 5

So, largest number would be: (x+2) = (5+2) = 7

In short, Your Final answer would be 7

Hope this helps!

Rounding decimals is very similar to rounding other numbers. if the hundredths and thousandths places of a decimal is forty-nine or less, they are dropped and the tenths place does not change. for example, rounding 0.843 to the nearest tenth would give 0.8. , your welcome !