Atriangle has vertices at r(1, 1), s(–2, –4), and t(–3, –3). the triangle is transformed according to the rule r0, 270°. what are the coordinates of s'?

Answer

The rule of rotation about the origin in counter-clockwise is given by:

The rule of rotation of about the origin in clockwise is given by:

Given the coordinates of triangle RST :

R(1, 1)

S(-2, -4)

T(-3, -3)

We have to find the coordinates of S'

Apply the rule of rotation 270 degree counterclockwise on RST:

To find the S'

Apply the rule of  rotation 270 degree clockwise we have;

Therefore, the coordinates of S' counterclockwise  is: (-4, 2) and clockwise is: (4, -2)

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0