The vertices of / are k(–1, 4), l(8, 3), and m(4, –1). / is rotated 270° counterclockwise about the origin to form /. what are the coordinates of the vertices of /?

The vertices of K'L'M' are K'(4,1),L'(3,-8) and M'(-1,-4).

Step-by-step explanation:

We are given that

The vertices of triangle KLM are K(-1,4),L(8,3) and M(4,-1).

When the triangle is rotated 270 degrees counterclockwise about the origin to form K'L'M'.

We have to find the vertices of K'L'M'.

When figure is rotated 270 degrees counterclockwise about the origin then the transformation rule is given by

By using this rule

The coordinates of K' (4,1)

The coordinates of L'(3,-8)

The coordinates of M'(-1,-4)

Hence, the vertices of K'L'M' are K'(4,1),L'(3,-8) and M'(-1,-4).

unless if u could do my questions, if not i wouldn't want to

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places