An ant looks up to the top of a tree at an angle of elevation of 40 degrees. if the ant is 30 feet from the base of the tree, what is the height of the tree, to the nearest tenth?

For the answer to the question above, this is a right triangle problem using the tangent function. 
Tan(x) = Opposite (O) / Adjacent (A) 
x = 40 degrees 
A = 30 ft 
Solve for O 
O= Tan (x) * A 
O = Tan (40) * 30 
Use your calculator or whatever method to get the tangent of 40 degrees (which is .84) 
O = .84 * 30 
O = 25.2 Ft

Hello there.

An ant looks up to the top of a tree at an angle of elevation of 40 degrees. If the ant is 30 feet from the base of the tree, what is the height of the tree, to the nearest tenth?

O = 25.2 

10.4 is the answer for you

The answer would be c.hope this .