Probability theory predicts that there is 77.6% chance of a particular soccer player making 2 penalty shots in a row. if the soccer player taking 2 penalty shots is simulated 2500 times, in about how many simulations would you expect at least 1 missed shot?

In about 560 simulations we would expect at least 1 missed shot.

Step-by-step explanation:

Probability theory predicts that there is 77.6% chance of a particular soccer player making 2 penalty shots in a row.

⇒ Probability of not missing a shot = 0.776

So, Probability of missing at least one shot = 1 - 0.776

                                                                      = 0.224

So, Chance of missing at least one shot = 22.4%

A shot is simulated 2500 times ⇒ n = 2500

Required simulations in which we would expect one shot missed = Probability of missing at least one shot × Number of simulations

⇒ Required simulations = 0.224 × 2500

                                          = 560

Hence, in about 560 simulations we would expect at least 1 missed shot.

where is the figure

answer: 1 + 1 = 11

step-by-step explanation: