Segment jk has coordinates j(3, –6) and k(–3, 2). when segment jk is dilated with a scale factor –4, what are the coordinates of j' and k'?

a ) j'(–1, –10) and k'(–7, –2)
b ) j'(7, –2) and k'(1, 6)
c ) j'(–3/4, 3/2) and k'(3/4, –1/2)
d ) j'(–12, 24) and k'(12, –8)

D) J'(–12, 24) and K'(12, –8)

Step-by-step explanation:

A dilation is a type of transformation that changes that size of a figure which is known as the pre-image to produce a new figure known as the image.

The rule to dilate a figure is to multiply the scale factor to the coordinates of the pre-image to get the coordinates of the image .

Therefore, If scale factor =-4

Then,  The coordinates of J' =

The coordinates of K' =

The coordinates of J' and K' are J'(–12, 24) and K'(12, –8).

Hence, D is the right answer.

3x3 = 9 and 2x2 = 4

step-by-step explanation:

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph